If it's not what You are looking for type in the equation solver your own equation and let us solve it.
w^2+9w-150=0
a = 1; b = 9; c = -150;
Δ = b2-4ac
Δ = 92-4·1·(-150)
Δ = 681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{681}}{2*1}=\frac{-9-\sqrt{681}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{681}}{2*1}=\frac{-9+\sqrt{681}}{2} $
| X(x+20)=90 | | -3x+15-(10+x)=35 | | 2x+7=7(x+1)-5x= | | 7z+3z=9z+7 | | 0.2(15x−7)=3x−9 | | 10c+146=5c | | -5-5y-1=14y-38-y | | 8x^2+5x-4=2x^2-8+1 | | 150+0.2x=70+0.6x | | (3x+7/6x)+(1/x)=1 | | 7/2x=9/4x | | a2-9a+18=0 | | -56-8X=99-13x | | -25-7x=23-3x | | 8x-3=6-4x | | 150x+0.2=70x+0.6 | | (5(x-3)/6)-X=1-x/9 | | 0.75k-2=9 | | 8y+1-3(-2y-1)=2(y-7) | | (2x+9)+10=(x+2 | | 4-x/2=8 | | 6x+5(1-6x)=2(1-13x)+13 | | X+(x+50)=300 | | 145.50x=2910 | | 9+2|4x−3|=19. | | 12-5x=18-7x | | -1.75y=-5/8 | | d/2−1=1 | | 15+x=33 | | 0.4x+0.1=0.5(x+4) | | -3(6x-4)+9x=3(x+7) | | 2y+2х=8;х=2,1,3 |